0=(w^2)+6w+5

Solution for 0=(w^2)+6w+5 equation:

0=(w^2)+6w+5

We move all terms to the left:

0-((w^2)+6w+5)=0

We add all the numbers together, and all the variables

-(w^2+6w+5)=0

We get rid of parentheses

-w^2-6w-5=0

We add all the numbers together, and all the variables

-1w^2-6w-5=0

a = -1; b = -6; c = -5;
Δ = b2-4ac
Δ = -62-4·(-1)·(-5)
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-4}{2*-1}=\frac{2}{-2}
=-1
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+4}{2*-1}=\frac{10}{-2}
=-5
$